Ordinary Differential Equations Find The Solution Of The Initial Value Problem Y 2x 1 2y Y 2 0 In Explicit Form Mathematics Stack Exchange
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyFor the equation y''y = 2x^2 a particular solution is y = x^2 Let's try to obtain a general solution assuming y = (x^2)V (x) Substituting in the equation obtain (x^2V'' 4xV' 2V)V = 2 where the term inside parentheses is an EuleroCauchy term Let x =e^t ,so y' (x) =y' (t)e^t , y'' (x) = (y'' (t)
